At the end of a race, a runner decelerates to a stop from a velocity of 8 m/s at a rate of 1.88 m/s2. How far does she travel in 8.6 s from when she begins decelerating?
Using
v = u + at
a = -1.88 m/s2
t = 8.6 s
u = 8 m/s
v2 - u2 = 2as
Stopping distance = 17.02 m
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At the end of a race, a runner decelerates to a stop from a velocity of...
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