ZuoTi.Pro
Question

suppose you were using the percentage difference method to determine the relationship between two varibles of...

suppose you were using the percentage difference method to determine the relationship between two varibles of interest arranged in a buvariate table. Are
there instances where you might find a very large percentage difference yet fail to find statistically significant results after conducting a chi-square test? If so, what factors would explain this?
math   Statistics-And-Probability   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

This can happen due to very small sample sizes

TS depends on sample sizes

when sample sizes are large, even when there is no practical difference in proportion, we could find significant difference

whereas when sample sizes are small, even high difference can't produce statistically significant results

0 0
Add a comment
Know the answer?
Add Answer to:
suppose you were using the percentage difference method to determine the relationship between two varibles of...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • Suppose the local state university wants to determine whether there is a relationship between a student’s...

    Suppose the local state university wants to determine whether there is a relationship between a student’s gender and a student’s major in college. The registrar was asked to randomly select 55 students and record their gender and major. The majors were grouped into categories of Natural Science (NS), Social Sciences (SS), and Humanities (H). Answer the following questions based on the results in the table below.                  NS                  SS                  H                       Total Men           11                    9                   3                          23 Women       9                   13                  10                       ...

  • Suppose you are testing whether there is a statistically significant difference in depression level between a...

    Suppose you are testing whether there is a statistically significant difference in depression level between a treatment and placebo group. You find a p-value of p=0.90. Do you reject or fail to reject the null hypothesis of no difference between groups? Why? Explain.

  • 3. As with the previous homework, we want to compare the average decrease in PSI between the two ...

    3. As with the previous homework, we want to compare the average decrease in PSI between the two teams. Create a new column for decrease in PST, defined as PST Pregarne minus PST_Halftime. Use "Analyze Fit Y by X", select the appropriate variables (see the notes if you have trouble with this), hit "OK", then select "t Test" from the drop down menu on the next screen. The results that you ignored in the previous homework are the results of...

  • Suppose there is an investigation into the relationship between taking aspirin and risk of heart attack....

    Suppose there is an investigation into the relationship between taking aspirin and risk of heart attack. Suppose 109 of the 11,036 aspirin takers had heart attacks, whereas 182 of the 11,033 placebo takers had them. The hypotheses for this example are given below. Null Hypothesis: There is no relationship between taking aspirin and risk of heart attack in the population. Alternative hypothesis: There is a relationship between taking aspirin and risk of heart attack in the population. (a) Calculate the...

  • Suppose there is an investigation into the relationship between taking aspirin and risk of heart attack....

    Suppose there is an investigation into the relationship between taking aspirin and risk of heart attack. Suppose 105 of the 11,034 aspirin takers had heart attacks, whereas 188 of the 11,035 placebo takers had them. The hypotheses for this example are given below. Null Hypothesis: There is no relationship between taking aspirin and risk of heart attack in the population. Alternative hypothesis: There is a relationship between taking aspirin and risk of heart attack in the population. (a) Calculate the...

  • For either independent-measures or repeated-measures designs comparing two treatments, the mean difference can be evaluated with...

    For either independent-measures or repeated-measures designs comparing two treatments, the mean difference can be evaluated with either at test or an ANOVA. The two tests are related by the equation F=12. The following data are from a repeated-measures study: Person Difference Scores 3 I 4 2 3 7 M = 4.00 T = 16 SS = 14 Treatment II 7 11 6 10 M 8.50 T-34 SS = 17 3 3 Mo 4.50 SS = 27.00 Use a repeated-measures t...

  • 2. Suppose you are interested in the relationship between weekly wage earnings in dol lars) and...

    2. Suppose you are interested in the relationship between weekly wage earnings in dol lars) and age (in years). You run a linear regression model where age is your dependent variable and earn is your independent variable. Answer the following questions about your regression results. earn = 239.16 5.20 × age (20.24) (0.57) Ip = 0.05, SER 287.21 (a) Interpret the coefficient for age. (b) Is the effect of age on earnings economically significant here? (Hint: think about how much...

  • A random sample of leading companies in South Korea gave the following percentage yields based on...

    A random sample of leading companies in South Korea gave the following percentage yields based on assets. 2.1 2.3 4.2 1.9 0.5 3.6 2.4 0.2 1.7 1.8 1.4 5.4 1.1 Use a calculator to verify that s2 ≈ 2.125 for these South Korean companies. Another random sample of leading companies in Sweden gave the following percentage yields based on assets. 2.2 3.8 3.9 1.1 3.9 2.8 2.3 3.5 2.8 Use a calculator to verify that s2 ≈ 0.909 for these...

  • 4. In this question, you will examine the relationship between survival and gender. (a) Obtain the contingency tab...

    4. In this question, you will examine the relationship between survival and gender. (a) Obtain the contingency table of survival by gender. Make sure that Row percent, Column percent, and Chi-Square options are checked in each contingency table dialog box. Paste the table into your report. Using a = 0.01, test that there was no relationship between survival and gender. State the null and alternative hypotheses. Report the value of the appropriate test statistic, the distribution of the test statistic...

  • You are doing a chi- square test for independence and find a significant result. What can conclude? A The null hypothesis is correct and there is no difference in the proportion of count in your singl...

    You are doing a chi- square test for independence and find a significant result. What can conclude? A The null hypothesis is correct and there is no difference in the proportion of count in your single row. B . The null hypothesis is incorrect and there is probably a relationship between the two variables of interest. C.The null hypothesis is correct and there is no relationship between your two variables of interest. D.The null hypothesis is incorrect and there is...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT