Solution:
1) HCOOH = CO2 + H2
The oxidation number of carbon in HCOOH is +2 and in CO2, it is +4.
HCOOH (+2) ===== CO2 (+4)
Hence, number of electron transfered = 4 - 2 = 2
Therefore, process is oxidation.
2) HCOOH + H2O ===== CH3OH + O2
The oxidation number of C in HCOOH is +2 and -2 in CH3OH
Therefore,
HCOOH ( +2) ===== CH3OH (-2)
Thus,
Number of electron transfered = -2 - (+2) = -4
Hence, 4 electrons are transfered and procwss in reduction.
How many electrons are transferred in each of these 2 reactions? 1. hcooh--> co2+h2 2. hcooh+h2o-->ch3oh+o2
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2 H2 + O2 → 2 H2O How many grams of H2O are produced from 284 grams of H2?
AH = -727 kJ Given that CH3OH (1) + 3/2 O2 (g) → CO2 (g) + 2 H2O(1) CO(g) + 1/2O2 (g) → CO2 (9) CH3OH(1) → CH3OH(g) AH = -284 kJ AH = 38 kJ H20 (1)→ H20 (9) AH = 44 kJ what is AH, in kJ, for the reaction CH3OH (g) + O2(g) →CO (g) + 2 H2O (9)
The Standard reactions Enthalpie from the following reactions are: 1) C + O2 = CO2. deltaH298 = -393.8 Kj/mol 2) H2 + 0.5 O2 = H2O deltaH298 = -286,2 Kj/mol 3) C6H6 + 7.5O2 = 6CO2 + 2H2O deltaH298 = -3267,7 Kj/mol How big is delta H298 for the following reaction: ?? C + ?? H2 = ?? C6H6 Help is really appreciated! Thanks!
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