Calculate the pH of a solution prepared by adding 0.0125 moles of hydrochloric acid to 100.0 mL of water.
Calculate the pH of a solution prepared by adding 0.0125 moles of hydrochloric acid to 100.0...
7. Calculate the pH of a solution prepared by adding 45.0 mL of 0.0250 M hydrochloric acid to 100.0 mL of 0.0300 M sodium benzoate. Answer options: 1.95; 2.07; 4.44; 5.88
TReferencer A solution is prepared by adding 49.9 ml concentrated hydrochloric acid and 19.7 ml concentrated nitric acid to 300 ml water More water is added until the final volume is 1.00 L. Calculate H".COH)and the pH for this solution. (Hint: Concentrated HCl is 38% HCI (by mass) and has a density of 1.19 g ml., concentrated HNO, is 70% HNO, (by mass) and has a density of 1.42 g/mL.] OH")= M pH-
Calculate the pH of a solution prepared by dissolving 0.876 moles of carbonic acid (H2CO3) and 0.543 moles of sodium hydrogen carbonate (NaHCO3) in water sufficient to yield 1.00 L of solution. The Ka of carbonic acid is 4.5x10^-7. Explain answer please
Top question. P1. (Sec. 16.2) What is the pH of a solution prepared by adding 0.45 moles of formic acid HCO2H, and 0.40 moles of sodium formate, NaCO,H, in enough water to make a 1.0-liter solution? (Formic Acid: K 1.81 10-) a) 4.32 b) 3.69 c) 5.52 d) 7.32 e) 9.11 P2. (Sec. 16.2) What is the pH of a solution prepared by adding 100 mL of a 0.25 M solution of sodium acetate, NaC2H,O2, into 110 mL of 0.30...
Calculate the pH of a solution made by adding 25.0 g of sodium formate, NaHCOO, to 400 ml of 0.64 M formic acid, нсоон. Answer: What is the pH of pure water at 25°C? Answer: When a small amount of acid is added to a non-buffered solution, there is a large change in pH. Calculate the pH when 22.2 ml of 0.0020 M HCl is added to 100.0 mL of pure water. Comment and hint in the general feedback Answer:
(10 pts) A solution is prepared by dissolving 1.239 grams of hydrochloric acid, HCI, in enough water to make 250.0 mL of solution. A 25.00 mL sample of this solution is diluted with water to a final volume of 100.0 mL. Now, you take 10.00 mL of that solution and dilute it to 100.00 mL What is the molarity of the final solution? (HCI 36.45 g/mol)
Find the pH of a formic acid solution that was is prepared by adding 0.280 g of formic acid to a volumetric flask and bringing the final volume to 1.44 L by adding water
A solution was prepared by dissolving 0.200 moles of sodium hypoch lorite (NaClO) in water to a final volume of 1.00 Liter. Ka 2.96x10 for hypochlorous acid (HCIO). Show equations and work steps for these calculations. 1) Calculate Kb of sodium hypochlorite. 2) Calculate the pH of the NaClO solution. 3) Calculate the pH if 10.0 mL of 1.00 M HCl is added to 100.0 mL of the original NACIO solution. 4) Calculate the pH if 20.0 mL of 1.00...
An aqueous solution contains 0.342 M ammonia. Calculate the pH of the solution after the addition of 5.28*10*2 moles of hydrochloric acid to 255 mL of this solution. (Assume that the volume does not change upon adding hydrochloric acid.) pH
A solution is made by adding 42.0 mL of concentrated hydrochloric acid (37.3 wt%, density 1.19 g/mL) to some water in a volumetric flask, and then adding water to the mark to make exactly 250 mL of solution. Calculate the concentration of this solution in molarity