Hamming Code: m = 1010 (4-bit message); odd-parity scheme; Compute Hamming Code on the sender’s side....
Hamming Code: m = 1010 (4-bit message); odd-parity scheme; Compute Hamming Code on the sender’s side. On the receiver’s side, detect and verify a 7th bit error-position in the transmitted data.
Homework Answers
Length of sequence-4
Number of parity bit required-4
length of code word=8
parity sceheme to be used,
P0=D0+D1+D3
P1=D0+D2+D3
P2=D1+D2+D3
P3=D0+D1+D2+P0+P1+P2
| D3 | D2 | D1 | D0 | P3 | P2 | P1 | P0 |
| 1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 |
| 1 | 1 | 1 | 0 | 0 | 1 | 0 | 0 |
| 1 | 1 | 0 | 1 | 0 | 0 | 1 | 0 |
| 1 | 0 | 1 | 1 | 0 | 0 | 0 | 1 |
So,the encoded value would be 10101010
Error in 7th bit detection means checking P1 collumn for correct value..As we can see in table its not showing an error.
| D3 | D2 | D1 | D0 | P3 | P2 | P1 | P0 |
| 1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 |
| 1 | 1 | 1 | 0 | 0 | 1 | 0 | 0 |
| 1 | 1 | 0 | 1 | 0 | 0 | 1 | 0 |
| 1 | 0 | 1 | 1 | 0 | 0 | 0 | 1 |
If it had a error in 7th bit,it would have been,
10101000
| D3 | D2 | D1 | D0 | P3 | P2 | P1 | P0 |
| 1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 |
| 1 | 1 | 1 | 0 | 0 | 1 | 1 | 0 |
| 1 | 1 | 0 | 1 | 0 | 0 | 1 | 0 |
| 1 | 0 | 1 | 1 | 0 | 0 | 0 | 1 |
here we can see P1 value changes
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