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A ball is thrown with a velocity of 9.0 m/s at an angle of 35-deg above...

A ball is thrown with a velocity of 9.0 m/s at an angle of 35-deg above the horizontal. What is the maximum height of the ball? Solve x and y component first, please give as much detailed explanation as possible, thanks

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Answer #1

y component (vertical component) of intial velocity will determine the maximum height  

= 5.16 m/s

-9.8 m/s2

At highest point

By equation of motion maximum height is given by

= (02 - 5.162)/(-19.6) = 1.36 m

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