2) You now need to construct confidence intervals for the mean monthly sales in this recent month for this type of shirt for the population of stores in the chain. You select a random sample of 65 stores that are members of the population you are studying. You find that the mean sales of the product in these stores for the month that is being studied are 417.6 shirts. You believe that the population standard deviation of the number of units sold is 75 units. Construct both 95% and 98% confidence intervals for the mean monthly sales per store of the shirt. Be sure to explain the meaning of these intervals. Comment upon the effect of the change in confidence level on the widths of your intervals.
2) You now need to construct confidence intervals for the mean monthly sales in this recent...
You wish to extend your study of the monthly sales of this particular type of men’s shirt so as to be able to compare the mean sales of the item at two types of store that make up the chain, superstores and regular stores. The population standard deviation of the monthly sales of the shirt at superstores is thought to equal 65 shirts, and the population standard deviation of the monthly sales of the shirt at regular stores is thought...
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 60 home theater systems has a mean price of $113.00. Assume the population standard deviation is $17.90. Construct a 90% confidence interval for the population mean
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 45 home theater systems has a mean price of $127.00. Assume the population standard deviation is $19.20. Construct a 90% confidence interval for the population mean. The 90% confidence interval...
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 60 home theater systems has a mean price of $135.00 . Assume the population standard deviation is $15.90 . A.) the 90% confidence interval is B.) the 95% confidence interval...
Confidence Intervals 9. Construct a 95 % confidence interval for the population mean, . In a random sample of 32 computers, the mean repair cost was $143 with a sample standard deviation of $35 (Section 6.2) Margin of error, E. <με. Confidence Interval: O Suppose you did some research on repair costs for computers and found that the population standard deviation, a,- $35. Use the normal distribution to construct a 95% confidence interval the population mean, u. Compare the results....
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 49 business days, the mean closing price of a certain stock was $113.41. Assume the population standard deviation is $11.13. a) The 90% confidence interval is (?) - (?)
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 39 business days, the mean closing price of a certain stock was $113.67. Assume the population standard deviation is $10.91. The 90% confidence interval is (1 , b). (Round to two decimal places as needed.)
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals From a random sample of 56 dates, the mean record high daily temperature in a certain city has a mean of 83.69°F. Assume the population standard deviation is 15.45°F. The 90% confidence interval is (Round to two decimal places as needed.)
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence ntervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals A random sample of 45 home theater systems has a mean price of $138.00. Assume the population standard deviation is 516.40. Construct a 90% confidence interval for the population mean. The 90% confidence interval...
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 64 dates, the mean record high daily temperature in a certain city has a mean of 85.80°F. Assume the population standard deviation is 15.07°F. The 90% confidence interval is (ID). (Round to two decimal places as needed.) The...