Facebook and Alibaba both had average stock prices of about $80 this year. Facebook has been...
Facebook and Alibaba both had average stock prices of about $80 this year. Facebook has been on the exchange for some time and seems to have a more consistent value. Alibaba, a recent addition to the exchange appears to fluctuate in price. A sample of 25 days of prices for, Facebook, had a standard deviation in price of $5. A sample of 31 days of prices of Alibaba, had a standard deviation of $8.50. Test the claim that the standard deviation of price for Aliaba is greater than for Facebook. Use a 5% level of significance.
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Facebook and Alibaba both had average stock prices of about $80
this year. Facebook has been...
A real estate agent has claimed that the average home prices in Lindville (L) and Jamesville...
A real estate agent has claimed that the average home prices in Lindville (L) and Jamesville (J) are equal. Suppose that a random sample of 18 Lindville homes resulted in a sample mean price of $235,000 with a sample standard deviation of $22,000. A random sample of 12 Jamesville homes resulted in a sample mean price of $245,000 with a sample standard deviation of $24,000. Test the real estate agent's claim at the 5% significance level. Assume that population variances...
Assume that a simple random sample has been selected from a normally distributed population and t...
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A random sample of 49 measurements from one population had a sample mean of 18, with...
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Problem 1: A physician claims that joggers' maximal volume oxygen uptake is greater than the average...
Problem 1: A physician claims that joggers' maximal volume oxygen uptake is greater than the average of all adults. A sample of 15 joggers had a mean oxygen uptake of 40.6 millimeters per kilogram (ml/kg) and a standard deviation of 6 ml/kg. If the mean oxygen uptake for all adults is 36.7 ml/kg, is there enough evidence to support the physician's claim at a 10% significance level? Assumption: parameter: null hypothesis Ho: alternative hypothesis Hj: test statistic: rejection region: calculated...
Suppose the national average dollar amount for an automobile insurance claim is $788.5. You work for...
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Comparing Grocery Prices Consumer groups often analyze store prices and compare the price of similar items in different stores. They share this information with other consumers or customers. Imagine that a consumer group suspects that there is a difference in prices between two grocery stores (Store A and Store B). To investigate, the consumer group identifies the prices of six identical items at Stores A and B. Since prices change over time, the consumer group gathers all data on a...
8-6 (Testing a Claim about a Standard Deviation or Variance) 1) Which T1-83. or TI-84 automatic...
8-6 (Testing a Claim about a Standard Deviation or Variance) 1) Which T1-83. or TI-84 automatic calculator function will you use in this section? a) 1-PropZTest b ) T-Test c) X-Test (d) None of these. 2) When a SRS of 40 people used 'Diet A' for one year, their weight losses had standard deviation 49 lbs. Use a 0.01 significance level to test the claim that the population standard deviation of all users of "Diet A' is 6.0, which is...
Assume that a simple random sample has been selected from a normally distributed population and test...
Assume that a simple random sample has been selected from a normally distributed population and test the given claim. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. In a manual on how to have a number one song, it is stated that a song must be no longer than 210 seconds. A simple random sample of 40 current hit songs results in a mean length of 227.6 sec and...
1.Child Health and Development Studies (CHDS) has been collecting data about expectant mothers in Oakland, CA...
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Assume that a simple random sample has been selected from a normally distributed population and test the given claim. Identify the null ad alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim In a manual on how to have a number one song, it is stated that a song must be no longer than 210 seconds. A simple random sample of 40 current hit songs results in a mean length of 227.2 sec and...
A random sample of 49 measurements from one population had a sample mean of 18, with sample standard deviation 5. An independent random sample of 64 measurements from a second population had a sample mean of 21, with sample standard deviation 6. Test the claim that the population means are different. Use level of significance 0.01. (a) What distribution does the sample test statistic follow? Explain. The standard normal. We assume that both population distributions are approximately normal with unknown...
Problem 1: A physician claims that joggers' maximal volume oxygen uptake is greater than the average of all adults. A sample of 15 joggers had a mean oxygen uptake of 40.6 millimeters per kilogram (ml/kg) and a standard deviation of 6 ml/kg. If the mean oxygen uptake for all adults is 36.7 ml/kg, is there enough evidence to support the physician's claim at a 10% significance level? Assumption: parameter: null hypothesis Ho: alternative hypothesis Hj: test statistic: rejection region: calculated...
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8-6 (Testing a Claim about a Standard Deviation or Variance) 1) Which T1-83. or TI-84 automatic calculator function will you use in this section? a) 1-PropZTest b ) T-Test c) X-Test (d) None of these. 2) When a SRS of 40 people used 'Diet A' for one year, their weight losses had standard deviation 49 lbs. Use a 0.01 significance level to test the claim that the population standard deviation of all users of "Diet A' is 6.0, which is...
Assume that a simple random sample has been selected from a normally distributed population and test the given claim. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. In a manual on how to have a number one song, it is stated that a song must be no longer than 210 seconds. A simple random sample of 40 current hit songs results in a mean length of 227.6 sec and...
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