Question

1. Evaluate 20 % 8          - (2, 4, 6, or 8)?

2. valuate 10 % 2           - (0, 2, 4, 5)?

3. Given the line of code: x = 5 + 5 / 5;     what value will be stored in x? - (2, 5, 6, or 10)?

4. Given the following code:

int a,b=10,c=3;

a = b/c;

what value will be stored in the variable a?         - (0, 3, 3.333333, or 4)?

5. Given the following code:

            Float a, b = 10.0, c = 3.0;

            A = b/c’

What value will be stored in the variable a?        -(0, 3, 3.333333, or 4)?

Answer 1

The solution to the above problem is:-

1.) 20 % 8 is 4.

2.)10 % 2 is 0.

3.) x = 6,as 5+ 5/5 i.e, 5+1 = 6.

4.)

int a,b=10,c=3;

a = b/c;

solution to the above code is 3. Because the data type of a is int.

5.)

float a, b = 10.0, c = 3.0;

a = b/c

sol:) as a's data type is float the value is 3.333333 is stored in it.

If any problem in understanding plz comment. I will try to explain. Thank you.