A skier starts at the top of a hill with height H, skies down and then climbs a smaller hill. The smaller hill is shaped like a large snowball with a radius R. As the skier skies straight down the side, at what point does she lose contact with the snowball and fly off at a tangent: at what angle α does a radial line from the center of the snowball to the skier make with the vertical? Ignore friction.
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A skier starts at the top of a hill with height H, skies down and then...
A skier starts from rest at the top of a hill that is inclined at 10.0° with respect to the horizontal. The hillside is 250 m long, and the coefficient of friction between snow and skis is 0.0750. At the bottom of the hill, the snow is level and the coefficient of friction is unchanged. How far does the skier glide along the horizontal portion of the snow before coming to rest?
A skier starts from rest at the top of a hill that is inclined at 9.8° with respect to the horizontal. The hillside is 240 m long, and the coefficient of friction between snow and skis is 0.0750. At the bottom of the hill, the snow is level and the coefficient of friction is unchanged. How far does the skier glide along the horizontal portion of the snow before coming to rest? m
63. SA skier starts at rest at the top of a large hemispherical hill (Fig. P7.63). Neglecting friction, show that the skier will leave the hill and become airborne at a distance h = R/3 below the top of the hill. Hint: At this point, the normal force goes to zero. Figure P7.63
H 11. A skier of mass 82 kg starts a downhill run from the top of a straight hill. The hill has a rough surface and has a length of 112 m. The top of the hill is 37.5 m above the lowest point. The speed of the skier at the top of the hill is - 183 and coefficient of kinetic friction between the skier's skis and the hill is 0.12. How fast is the skier moving at the...
A skier with mass 64.0 kg starts at rest at the top of an 842 m long ski slope, which makes an angle 13.0 ∘ with the horizontal. A typical coefficient of friction between skis and snow is 5.20×10−2. skiers don't go straight down the hill- they zigzag back and forth. Even though they still end up at the bottom of the hill, they've lost more energy to friction because friction is a non-conservative force. Let's say due to zigzagging,...
A 90 kg skier at the top of a 400 m icy hill slides down, through a 20 m patch of snow (µk= 0.25) and hits a 20 m long jump ramp at a 45° incline. a) (10 points) How far from the edge of the ramp does the skier land (m)? b) (5 points) How high will he get of the ground (max height (m)) ?
A 90 kg skier at the top of a 400 m icy hill slides down, through a 20 m patch of snow (uk-0.25) and hits a 20 m long jump ramp at a 45° incline. a) (10 points) How far from the edge of the ramp does the skier land (m)? b) (5 points) How high will he get of the ground (max height (m)) ? 400 m 20 m 45° X 20 m
A 90 kg skier at the top of a 400 m icy hill slides down, through a 20 m patch of snow (uk= 0.25) and hits a 20 m long jump ramp at a 45° incline. a) (10 points) How far from the edge of the ramp does the skier land (m)? 400 m 20 m 45° X 20 m b) (5 points) How high will he get of the ground (max height (m)) ?
A 90 kg skier at the top of a
400 m icy hill slides down, through a 20 m patch of snow (µk= 0.25)
and hits a 20 m long jump ramp at a 45° incline. a) (10 points) How
far from the edge of the ramp does the skier land (m)? b) (5
points) How high will he get of the ground (max height (m)) ?
Ho 400 m 20 m 45° X 20 m
8. A skier of weight 150 lbs starts at the top of a mountain 100 m high, and slides down its slope of 30° with a coefficient of kinetic friction of 0.03. How long does it take the skier to reach the bottom of the mountain.