pH of urine is 5.7, while lime juice has a pH of 2.0. The urine sample has:
a) approximately 100,000 times lower [H+] than the lime juice
b) approximately 5,000 times lower [H+] than the lime juice
c) approximately 3.5 times lower [H+] than the lime juice
d) approximately 0.285 times the [H+] as the lime juice
e) approximately 5 times lower [H+] than the lime juice
pH of urine = 5.7
pH = - log [H+]
[H+] urine = 10^-pH = 10^-5.7
= 1.995 x 10^-6
pH of lime = 2.0
pH = - log [H+]
[H+] lime = 10^-pH = 10^-2.0
= 0.01
[H+]lime / [H+]urine = 0.01/(1.995 x 10^-6)
= 5012
[H+]lime = 5012 * [H+]urine
urine sample approximately 5,000 times lower [H+] than the lime juice
Option B is the correct answer
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