Question

Review Part B The gastric juice in your stomach has a pH of 2.0. This acidity is due to the secretion of protons into the stomach by the epithelial cells of the gastric mucosa. Epithelial cells have an internal pH of 7.0 and a membrane potential -70 mV (inside is negative) and function at body temperature (37 C). Calculate the free energy change associated with the secretion of 1 mole of protons into gastric juice at 37 C, outside zFV AGoutwardRTIn m Hide Express your answer using one decimal place. ? AGward kcal/mol Submit Previous Answers Request Answer

Answer 1

Given that PH Aps I aastric juice in stomach is 2.0 wa noo that pH= 1010 CH1 [Ht =lo-PH Outtide Qutiaacd ofatne juice The CH+1 So CHJoud outside 10 M lo-2.0 uave internal pH 7.0 Also Epithelia! ceuls CH+Jnside 10 PH10 M tal = Vm -70m V ALSO, it is tven that neubrane potenti Vm = -70 X 10-3 V pretons moles -Z=1uoP ne Pmpereturt fi enedchae T: 37°c 37+273 - 310K iven by So, the AG outward RTLn [HtJoutsid ZF Vm [HtJ iaside whire F Faraday coutont (96500 C mo 1 ) coutant (8-314 T/(mol -K) R univrsal AGutstd AGeutta AGoOutnard x96 500X 70x 10 1 mo x 310 K ln 10-2 &.314 J 10-7 mol-K 3 AGoutward 29672 72 6755 J J+ 36.427 Aleoutword 20 417 KJ Or, since IKI 0.23 8 KCa 8.7 So, AGeuord - as