Question

gastric juice is made up of substance

Question 11 of 11 > Gastric juice is made up of substances secreted from parietal cells, chief cells, and mucous-secreting cells. The cells secrete HCI, proteolytic enzyme zymogens, mucin, and intrinsic factor. The pH of gastric juice is acidic, between 1-3. If the pH of gastric juice is 2.3, what is the amount of energy (AG) required for the transport of hydrogen ions from a cell (internal pH of 7.4) into the stomach lumen? Assume that the potential difference across the membrane separating the cell and the interior of the stomach is-60.0 mV (inside of the celll is negative relative to the lumen of the stomach). Assume that the temperature is 37 °C. The Faraday constant is 96.5 kJ/(V-mol) and the gas constant is 8.314 x 103 k/(mol-K) Express your answer in kilojoules per mole. kl/mol AG =

Answer 1

Given The pH of gastric juice is 2.3. - Internal pH = 7:4 The interior of the stomach.i8-60.0 mr Temperature (9) = 37°c = 37+273k 310.k . .... . . The Faraday constant : 965 koiv.mod The gas constant = 8.314x 10-kolmolik Concentration of it inside = 1074 53.98x10-07 concentration d #tout side = 102.3 E : 55.01X103m. hep = (**Tout side pow, [H*Inside

3.98x10-BM 5.018 10 3M = 7.94x10-6 . :. heq = 7.94 x10367 AG = - RT ln keg Where Ris Gas constant :::T= Temperature => AG, = (-8.314x10 9 kg ) (310k) In 17.94155) => AG, = (-8.314*10*3 ks/mol) (310) (-11.7435) 4= 30.26 kolmet AG,= - NF E where F= Faraday constant

=> 492 = (1) (96.5 komod.v) (-60.0x16 %) .. AG. 55:79 kolmel Amount of Energy gequired for the transport of hy drogen ions form a cell in to the stomach lumen = 30.26 kolmel + 5.79 helmel = 36.05 kolmol. Z please rate me...
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