A proton with a kinetic energy of 6.1 ✕ 10-16 J moves
perpendicular to a magnetic field of 3.9 T. What is the radius of
its circular path?
cm
A wire with a current of 2.8 A is at an angle of 38.5° relative
to a magnetic field of 0.88 T. Find the force exerted on a 2.13 m
length of the wire.
N
A proton with a kinetic energy of 6.1 ✕ 10-16 J moves perpendicular to a magnetic...
Find the radius of a proton's orbit when it moves perpendicular to a magnetic field of 0.66 T with a speed of 6.48×105 m/s . A wire with a current of 2.8 A is at an angle of 36.0 ∘ relative to a magnetic field of 0.85 T . Find the force exerted on a 2.35 −m length of the wire.
A proton with a kinetic energy of 4.9×10−16 Jmoves perpendicular to a magnetic field of 0.26 T Part A What is the radius of its circular path Express your answer using two significant figures. 2 cIn Submit My Answers Give Up
An electron has a kinetic energy of 1.81E-17 J. It moves on a circular path that is perpendicular to a uniform magnetic field of magnitude 5.09E-5 T. Determine the radius of the path.
An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.275 T. If the kinetic energy of the electron is 3.10 10-19 J, find the speed of the electron and the radius of the circular path.
1. A proton, which moves perpendicular to a magnetic field of 1.29 T in a circular path of radius 0.073 m, has what speed? (qp = 1.6 · 10 -19 C and mp = 1.67 · 10 -27 kg) 2. A 74.0-m-long wire carrying a current of 3.80 A will be accompanied by a magnetic field of what strength at a distance of 0.0270 cm from the wire? Give your answer in Gauss, G. (magnetic permeability in empty space µo...
An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.275 T. If the kinetic energy of the electron is 4.30 ✕ 10−19 J, find the speed of the electron and the radius of the circular path. (a) the speed of the electron m/s (b) the radius of the circular path μm
An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.300 T. If the kinetic energy of the electron is 3.60 ✕ 10−19 J, find the speed of the electron and the radius of the circular path. (a) the speed of the electron (m/s) (b) the radius of the circular path (μm)
An electron of kinetic energy 26.0 keV moves in a circular orbit perpendicular to a magnetic field of 0.395 T. Find the radius of the orbit. Find the period of the motion.
An electron of kinetic energy 36.0 keV moves in a circular orbit perpendicular to a magnetic field of 0.350 T. Find the radius of the orbit. Find the period of the motion.
A proton moves at 7.20 ✕ 107 m/s perpendicular to a magnetic field. The field causes the proton to travel in a circular path of radius 0.810 m. What is the field strength (in T)?