Question

write a java program that converts a floating point number to the simple model of the floating point

The simple model uses 1 bit for sign, 5 bits for exponents and 8 bits for significand

Answer 1

Solution(s):

Java Program

import java.util.Scanner;
public class conversionClass
{
     public static void main(String[]args)
     {
        Scanner scanInput = new Scanner(System.in);
        double decimalNum;
        int valueBit;
        String stringOfBits;
      
        System.out.println("Please enter the decimal that needs to convert in single precision floating point");
      
        decimalNum = scanInput.nextInt();
        float f = (float)decimalNum;
        valueBit = Float.floatToIntBits(f);
        stringOfBits = Integer.toBinaryString(valueBit);
        System.out.println("Single precision floating point:" + stringOfBits);
      
        System.out.println("Please enter the decimal that needs to convert in double precision floating point");
      
        decimalNum = scanInput.nextInt();
         stringOfBits = Long.toString(Double.doubleToLongBits(decimalNum), 2);
        System.out.println("double precision floating point:" + stringOfBits);   
      
     }
}