A particular I.R.S. auditor collects additional money from an average of 70% of the individuals she audits. What formula would you use to find the probability that she will collect additional money from all of the next 3 separate and independently audited individuals?
P(A) = (# examples of A) ÷ (total # outcomes possible)
x̄ - z(σ ÷ √n) < µ < x̄ + z(σ ÷ √n)
χ² = ∑ (fij – eij)2 ÷ eij
P (x out of n) = [n! ÷ x!(n – x)!] [px] [(1 – p)n-x]
Solution:
P (x out of n) = [n! ÷ x!(n – x)!] [px] [(1 – p)n-x]
A particular I.R.S. auditor collects additional money from an average of 70% of the individuals she...
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