Calculate the freezing point (in degrees C) of a solution made by dissolving 2.56 g of sucrose in 37.2 g of water. The Kfp of the solvent is 1.86 K/m and the normal freezing point is 273 K. Enter your answer to 2 decimal places.
Calculate the freezing point (in degrees C) of a solution made by dissolving 2.56 g of...
Calculate the freezing point (in degrees C) of a solution made by dissolving 3.79 g of anthracene{C14H10} in 81.1 g of benzene. The Kfp of the solvent is 5.12 K/m and the normal freezing point is 5.5 degrees C
17 Marks: 1 What is the freezing point of water made by dissolving 10.74 g of magnesium chloride in 86.59 g of water? The freezing-point depression constant of water is 1.86 °CIm Answer: 18 Marks: 1 What is the freezing point of water made by dissolving 16.31 g of sodium chloride in 93.18 g of water? The freezing-point depression constant of water is 1.86 °C/m. Answer 19 Marks: 1 What is the freezing point of water made by dissolving 46.18...
A solution is made by dissolving 0.749 mol of nonelectrolyte solute in 861 g of benzene. Calculate the freezing point, Tf, and boiling point, Tb, of the solution. Constants may be found here. Solvent Formula Kf value* (°C/m) Normal freezing point (°C) Kb value (°C/m) Normal boiling point (°C) water H2O 1.86 0.00 0.512 100.00 benzene C6H6 5.12 5.49 2.53 80.1 cyclohexane C6H12 20.8 6.59 2.92 80.7 ethanol C2H6O 1.99 –117.3 1.22 78.4 carbon tetrachloride CCl4 29.8 –22.9 5.03 76.8...
What is the freezing point of water made by dissolving 46.62 g of sugar (C12H22O11) in 91.32 g of water? The freezing-point depression constant of water is 1.86 oC/m.
2a Calculate the freezing point of a solution that is made from 39.9 g of a nonelectrolyte (ℳ = 142.4701 g/mol) dissolved in 186.3 g of solvent. The solvent freezes at 1.24 °C and its Kf value is 2.09 °C/m. Report your answer to TWO places past the decimal. 2b The solubility of carbon dioxide gas at 37.3 °C and a carbon dioxide pressure of 554 mmHg is 4.04 × 10−3 g/L. What is the Henry's Law constant in mol⋅L−1⋅atm−1?...
1 point What is the freezing point of an aqueous solution prepared by dissolving 113 g potassium carbonate (K,CO3, 138 g/mol) in 2.50 kg water. Use the ideal van 't Hoff factor. [K (water) - 1.86 °C/m) -1.83 °C +1.83 °C -0.609 °C -1.23 °C Previous Submit
A solution is made by dissolving 0.592 mol of nonelectrolyte solute in 767 g of benzene. Calculate the freezing point, Te, and boiling point, Tb, of the solution. Constants can be found in the table of colligative constants. T = Colligative Constants Constants for freezing-point depression and boiling-point elevation calculations at 1 atm: Solvent Formula Kf value* Normal freezing Kb value Normal boiling (°C/m) point (°C) (°C/m) point (°C) water H20 1.86 0.00 0.512 100.00 benzene 5.12 5.49 2.53 80.1...
A Review Constants Periodic Table The changes in boiling point (AT) or freezing point (AT) in degrees Celsius from a pure solvent can be determined from the equations given here, respectively: AT) = m x K = moles of solute XK K. kilograms of solvent Since pure water boils at 100.00 °C, and since the addition of solute increases boiling point, the boiling point of an aqueous solution, Th, will be T - (100.00+AT) 'C Since pure water freezes at...
What is the freezing point (°C) of a solution prepared by dissolving 11.3 g of in 115 g of water? [Use these Molar Masses: Ca = 40, N = 14, O = 16. Also, the molal freezing point depression constant for water is 1.86 °C/m.]
What is the freezing point (in K) of a solution made by dissolving 19.831g of CCl4 in 130.0 g of benzene? Pure benzene has a freezing point of 5.5°C and a Kf = 5.12 °C/m. Write your answer in Kelvin with 4 sig figs!