A scientist prepared a 0.037 M NH4Cl salt solution by dissolving the solid salt in water. Calculate the pH at 25°C for the solution, given that the Kb of ammonia, NH3, is 1.8 ✕ 10−5.
A scientist prepared a 0.037 M NH4Cl salt solution by dissolving the solid salt in water....
What is the pH of a buffer system prepared by dissolving 10.70 grams of NH4Cl and 35.00 mL of 12 M NH3 in enough water to make 1.000 L of solution? Kb = 1.80 × 10-5 for NH3. 9.26 9.58 8.93 11.69
Calculate the pH of a buffer prepared by dissolving 0.10 mol of NH4Cl in 1.00 L of 0.15 M NH3. Kb = 1.8 x 10 % for NH3. O a. 11.34 O b. 2.72 O ü O ö Oe. 4.56
1. Calculate the pH of a solution prepared by dissolving 0.850 mol of NH3 and 0.350 mol of NH4Cl in water sufficient to yield 1.00 L of solution. The Kb of ammonia is 1.77 × 10-5 (a) 5.137 (b) 4.367 (c) 9.633 (d) 8.781 (e) 8.863 2. A 0.1 M solution of which of the following willl have the highest pH? (a) KCN, Ka of HCN = 4.0x10-10 (b) NH4NO3, Kb of NH3 = 1.8x10-5 (c) NaOAc, Ka of HOAc...
NH3 is a weak base (Kb = 1.8 × 10–5) and so the salt NH4Cl acts as a weak acid. What is the pH of a solution that is 0.048 M in NH4Cl at 25 °C? pH=_______?
A buffer solution is prepared by dissolving 1.600 g of ammonium chloride (NH,CI) into 100.00 mL of a 0.160 M solution of ammonia (NH3). The Kb of ammonia is 1.8 x 10-5. What is the pH of the solution?
NH3 is a weak base (Kb = 1.8 × 10-5) and so the salt NH4Cl acts as a weak acid. What is the pH of a solution that is 0.018 M in NH4Cl at 25 C?
NH3 is a weak base (Kb = 1.8 × 10–5) and so the salt NH4Cl acts as a weak acid. What is the pH of a solution that is 0.044 M in NH4Cl at 25 °C?
NH3 is a weak base (Kb = 1.8 x 10-5) and so the salt NH4Cl acts as a weak acid. What is the pH of a solution that is 0.053 M in NH4Cl at 25 ℃? Number pH =
NH3 is a weak base (Kb = 1.8 x 10-5) and so the salt NH4Cl acts as a weak acid. What is the pH of a solution that is 0.022 M in NH4CI at 25 °C? Number pH-
What is the pH of a solution which is prepared by dissolving .85 mol of NH3 and .30 mol of NH4CL in water to yield 1.00 L of solution? (The Kb is 1.77x10^-5)