Three capacitors C1, C2, and C3 are strung in parallel. Their values are 4 μF, 6 μF, and 12 μF respectively. If I attach the 10 V battery, what will be the new charge on each capacitor? (f) Finally, I disconnect the battery and separate all the capacitors, leaving them still charged. Then I insert a dielectric of mica (κ = 4.5) into all of the capacitors, being careful not to change the charge. What is the new voltage on each?
Three capacitors C1, C2, and C3 are strung in parallel. Their values are 4 μF, 6...
Three capacitors of capacitance C1=3.50 μF, C2 =9.00 μF, and C3=12.0 μF are connected to a 40.0 V battery as shown in the figure. Calculate the charge on C3. 2.45×10-4 C Y Calculate the voltage across C1. You can use your answer to the previous problem to find the voltage across C3, and then find the voltage across C1. Or you can find the charge across the parallel combination of C1 and C2, then find the voltage.
Three capacitors of capacitance C1=3.50 μF, C2 =7.00 μF, and C3=16.0 μF are connected to a 30.0 V battery as shown in the figure. Calculate the charge on C3.
Three capacitors of capacitance C1=3.50 μF, C2 =9.50 μF, and C3=11.0 μF are connected to a 40.0 V battery as shown in the figure.1. Calculate the charge on C3.2. Calculate the voltage across C1
Capacitors C1, C2, and C3 are connected purely in parallel to a 13 volt battery. The charge in C2 is 2 times larger than the charge in C1, and C3 has a factor of 9 times less charge than C2. The total stored energy in all three capacitor is 160 micro-joules. What is the charge in C3 in micro-coulombs?
Two air-filled parallel-plate capacitors with capacitances C1 and C2 are connected in series to a battery that has voltage V; C1 = 3.00 μF and C2 = 6.00 μF. The electric field between the plates of capacitor C2 is E02. While the two capacitors remain connected to the battery, a dielectric with dielectric constant K = 4 is inserted between the plates of capacitor C1, completely filling the space between them. After the dielectric is inserted in C1, the electric...
Two capacitors, C1 = 4.41 μF and C2 = 13.9 μF, are connected in parallel, and the resulting combination is connected to a 9.00-V battery. (a) Find the equivalent capacitance of the combination. μF (b) Find the potential difference across each capacitor. V1 = V V2 = V (c) Find the charge stored on each capacitor. Q1 = μC Q2 = μC
Two capacitors, C1 = 4.35 μF and C2 = 12.5 μF, are connected in parallel, and the resulting combination is connected to a 9.00-V battery. (a) Find the equivalent capacitance of the combination. μF (b) Find the potential difference across each capacitor. V1 = V V2 = V (c) Find the charge stored on each capacitor. Q1 = μC Q2 = μC
Two capacitors, C1 = 4.74 μF and C2 = 10.8 μF, are connected in parallel, and the resulting combination is connected to a 9.00-V battery. (a) Find the equivalent capacitance of the combination. μF (b) Find the potential difference across each capacitor. V1 = V V2 = V (c) Find the charge stored on each capacitor. Q1 = μC Q2 = μC
In this circuit, C1=10μF, C2=12 μF, and C3=15 μF. The voltage across the batteries is 20V. a. Find the voltage across each capacitor and the charge on each one. b. These three capacitors are replaced by two equal capacitors in parallel. What should the capacitance of these two capacitors be for the two circuits to be equivalent? C1 C2 C3
Four capacitors (C1 = 9.0 μF, C2= 7.0 μF, C3 = 12 μF, and C4 = 30 μF)are connected to a 18-V battery as shown below. (a) Calculate the equivalent capacitance of the circuit. (b) Determine the voltages across each capacitor. (c) Find the charge on each capacitor. Please, show all the important physics steps to earn full credits.