If ΔHΔHDH = -50.0 kJkJ and ΔSΔSDS = -0.300 kJ/KkJ/K , the reaction is spontaneous below a certain temperature. Calculate that temperature.
Express your answer numerically in kelvins.
If ΔHΔHDH = -50.0 kJkJ and ΔSΔSDS = -0.300 kJ/KkJ/K , the reaction is spontaneous below...
If ΔH = -70.0 kJ and ΔS = -0.300 kJ/K , the reaction is spontaneous below a certain temperature. Calculate that temperature. Express your answer numerically in kelvins.
If AH = -70.0 kJ and AS = -0.200 kJ/K , the reaction is spontaneous below a certain temperature. Calculate that temperature. Express your answer numerically in kelvins.
If ΔH = -80.0 kJ and ΔS = -0.500 kJ/K , the reaction is spontaneous below a certain temperature. Calculate that temperature Express your answer numerically in kelvins.
Part C If ΔH = -80.0 kJ and ΔS = -0.200 kJ/K , the reaction is spontaneous below a certain temperature. Calculate that temperature. Express your answer numerically in kelvins.
Part c Part C If AH = -60.0 kJ and AS = -0.500 kJ/K, the reaction is spontaneous below a certain temperature. Calculate that temperature. Express your answer numerically in kelvins. ► View Available Hint(s) VO ADD A A O O ? 233.3 Submit Previous Answers X Incorrect; Try Again; 5 attempts remaining
If ΔH = -70.0 kJ and ΔS = -0.500 kJ/K , the reaction is spontaneous below a certain temperature. Calculate that temperature.
If ΔH=−80.0kJmol−1 Δ H = − 80.0 k J m o l − 1 and ΔS=−0.500kJK−1mol−1 Δ S = − 0.500 k J K − 1 m o l − 1 , the reaction is spontaneous below a certain temperature. Calculate that temperature. Express your answer numerically in kelvins.
Part A: ΔH∘rxn= 121 kJ ; ΔS∘rxn=− 246 J/K ; T= 291 K Express your answer as an integer. Part B: ΔH∘rxn=− 121 kJ ; ΔS∘rxn= 246 J/K ; T= 291 K Express your answer as an integer. Part C: ΔH∘rxn=− 121 kJ ; ΔS∘rxn=− 246 J/K ; T= 291 K Express your answer as an integer. Part D: ΔH∘rxn=− 121 kJ ; ΔS∘rxn=− 246 J/K ; T= 600 K Express your answer as an integer. Part E: Predict whether...
At what temperatures will a reaction be spontaneous if AH = +59.0 kJ and 45º = -25.2 JK? at The reaction will be spontaneous at any temperature. The reaction will never be spontaneous O All temperatures below 94.1 K All temperatures above 94.1 K O Temperatures between 12.7 K and 135 K ot DE Submit Answer Try Another Version 1 item attempt remaining ot ot of of
Part B A certain reaction with an activation energy of 205 kJ/mol was run at 505 K and again at 525 K. What is the ratio of f at the higher temperature to f at the lower temperature? Express your answer numerically using one significant figure.