In a random sample of 40 fast food joints, the mean price of a burger is $3.00 and the population standard deviation is 1.
What distribution do you use?
Construct a 95% confidence interval.
In a random sample of 40 fast food joints, the mean price of a burger is...
A random sample of 13 customers in a Kentucky fast food restaurant revealed an average bill of OMR 18.75 per person. The population standard deviation is OMR5.4. Estimate 98% confidence interval for the mean bill of all customers. A random sample of ' n' customers in a Kentucky fast food restaurant revealed an average bill of OMR & per person. The population standard deviation is OMR 6. Estimate 98% confidence interval for the mean bill of all customers. n X...
In a random sample of 11 people, the mean driving distance to work was 25.2 miles and the standard deviation was 7.3 miles. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 95% confidence interval for the population mean. Identify margin of error Construct a 95% confidence interval for the population mean (___,___)
In a random sample of six mobile devices, the mean repair cost was $80.00 and the standard deviation was $12.00. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 95% confidence interval for the population mean. Interpret the results. The 95% confidence interval for the population mean mu is
The amount that a sample of eight customers spent for lunch ($) at a fast-food restaurant is shown below: 67, 52, 86, 52, 88, 32, 28, 43 a. Find the sample mean ??? b. Find the sample standard deviation S c. Construct a 95% confidence interval estimate for the population mean ?
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 45 home theater systems has a mean price of $127.00. Assume the population standard deviation is $19.20. Construct a 90% confidence interval for the population mean. The 90% confidence interval...
6.2.19-T Question Help In a random sample of four microwave ovens, the mean repair cost was $85.00 and the standard deviation was $13.00. Assume the population is normally distributed and use a t-distribution to construct a 99% confidence interval for the population mean μ. What is the margin of error of μ? Interpret the results. The 99% confidence interval for the population mean μ is (DD (Round to two decimal places as needed.) 6.2.21-T Question Help In a random sample...
#17 You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals. A random sample of 34 gas grills has a mean price of $648.20 Assume the population standard deviation is $56.70 The 90% confidence interval is (______,______).
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals. A random sample of 45 gas grills has a mean price of $648.40 Assume the population standard deviation is $56.50 The 90% confidence interval is
In a random sample of eleven cell phones, the mean full retail price was $515.50 and the standard deviation was $212.00. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 90% confidence interval for the population mean mu. Interpret the results.
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 60 home theater systems has a mean price of $135.00 . Assume the population standard deviation is $15.90 . A.) the 90% confidence interval is B.) the 95% confidence interval...