Question

The pressure inside a pressure cooker is 29.7 psi. a) Express this pressure in atm. ( 1 atm = 14.7 psi b) Express this pressure in mmHg. ( 1 atm = 760 mmHg) c) If the gas inside the pressure cooker occupies a volume of 2.0L at a temperature of 107 degrees centigrade, how many moles of gas are inside the pressure cooker? R = 0.0821 L atm/mol.K k=Degrees Centigrade +273.15

Answer 1

Part A) 1 atm = 14.7 psi ; 1 psi = 1 / 14.7 atm

so 29.7 psi = 29.7 / 14.7 atm = 2.02 atm

Part B) 14.7 psi = 760 mmHg ; 1 psi = 760 mmHg / 14.7

29.7 psi = (29.7 * 760) / 14.7 mmHg = 1.53 * 10³ mmHg

Part C) PV = nRT

n = PV / RT

V = 2.0L

P = 2.02 atm

T = 107^oC = 380.15 K

R = 0.0821  L atm/mol.K

n = 2.02 atm * 2.0L / (0.0821  L atm/mol.K) * 380.15 K

n = 0.129 moles

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