What is the pH at which a buffer composed of NH3 and NH4+ would be most effective at resisting pH change? Round your answer to 2 decimal places.
The buffer is most effective when pH is equal to pKa
Kb of NH3 is 1.8*10^-5
lets find Ka of NH4+ and then its pKa
use:
Ka = Kw/Kb
Kw is dissociation constant of water whose value is 1.0*10^-14 at 25 oC
Ka = (1.0*10^-14)/Kb
Ka = (1.0*10^-14)/1.8*10^-5
Ka = 5.556*10^-10
use:
pKa = -log Ka
= -log (5.556*10^-10)
= 9.2553
Answer: 9.26
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