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A machine that puts corn flakes into boxes is adjusted to put an average of 15.3...

A machine that puts corn flakes into boxes is adjusted to put an average of 15.3 ounces into each box, with standard deviation of 0.23 ounce. If a random sample of 15 boxes gave a sample standard deviation of 0.36 ounce, do these data support the claim that the variance has increased and the machine needs to be brought back into adjustment? (Use a 0.01 level of significance.) (i) Give the value of the level of significance. 0.01 State the null and alternate hypotheses. H0: σ2 = 0.0529; H1: σ2 ≠ 0.0529 H0: σ2 = 0.0529; H1: σ2 < 0.0529 H0: σ2 = 0.0529; H1: σ2 > 0.0529 H0: σ2 < 0.0529; H1: σ2 = 0.0529 (ii) Find the sample test statistic. (Round your answer to two decimal places.) 3.47 (iii) Find or estimate the P-value of the sample test statistic. P-value > 0.100 0.050 < P-value < 0.100 0.025 < P-value < 0.050 0.010 < P-value < 0.025 0.005 < P-value < 0.010 P-value < 0.005 (iv) Conclude the test. Since the P-value ≥ α, we fail to reject the null hypothesis. Since the P-value < α, we reject the null hypothesis. Since the P-value < α, we fail to reject the null hypothesis. Since the P-value ≥ α, we reject the null hypothesis. (v) Interpret the conclusion in the context of the application. At the 1% level of significance, there is insufficient evidence to conclude that the variance has increased and the machine needs to be adjusted.  

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Answer #1

i) H0: σ2 = 0.0529; H1: σ2 > 0.0529

ii) sample test statistic =(n-1)*(S/σ)2 =(15-1)*(0.36/0.23)2 =34.30

iii)

P-value < 0.005

(iv)

Since the P-value < α, we reject the null hypothesis

(v)

. At the 1% level of significance, there is sufficient evidence to conclude that the variance has increased and the machine needs to be adjusted

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