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Particle A is at rest, and particle B collides head-on with it. The collision is completely...

Particle A is at rest, and particle B collides head-on with it. The collision is completely inelastic, so the two particles stick together after the collision and move off with a common velocity. The masses of the particles are different, and no external forces act on them. The de Broglie wavelength of particle B before the collision is 1.8 × 10-34 m. What is the de Broglie wavelength of the object that moves off after the collision?

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Answer #1

DeBroglie wavelength = h/p where p is momentum and h is Planck's constant.

The momentum of combined particles is same as momentum of B as A had zero momentum initially and momentum will be conserved.

So DeBroglie wavelength will be same

= 1.8 × 10-34 m answer

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