Question

Driving home from school one day, you spot a ball rolling out into the street (see the figure (Figure 1)). You brake for 1.50 s , slowing your 980-kg car from 16.0 m/s to 9.50 m/s. What was the magnitude of the average force exerted on your car during braking? What was the direction of the average force exerted on your car during braking? How far did you travel while braking?

Answer 1

decceleration of the car

a = ( u - v) /t

a = ( 16 - 9.5) / 1.5

a = 4.33 m/s^2

force

F = ma = 4246.67 N

=====

b)

direction of braking force is opposite to the motion of the car

=====

c)

d = ut - 0.5 at^2

d = 16 * 1.5 - 0.5* 4.33* 1.5^2

d = 19.128 m

=====

Comment in case any doubt, will reply for sure. Goodluck