the equilibrium constant for the reaction below decreases from 20570.0 at 440.0 C to 23.0 at...
the equilibrium constant for the reaction below
decreases from 20570.0 at 440.0 C to 23.0 at 900.0 c
4NO + 3O2 .....2N2O5
from this data...calculate the value of change of heat for the
reaction
Homework Answers
The relation between the equilibrium constant and heat for
the reaction is given by Van't Hoff equation
ln(K2/K1) = 
H/R[1/T1-1/T2] or
log(K2/K1) = (H/(2.303*R)*(1/T1-1/T2)
K2 = 23 T2 = 1173 K
K1 = 20570 T1 = 713 K
H
= value of change of heat for the reaction
log(23/20570) = (H/(2.303*8.314)*(1/713-1/1173)
The value of change of heat for the reaction,
Hrxn = -102.748 KJ
Add Answer to:
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