Question

A survey found that​ women's heights are normally distributed with mean 63.8 in. and standard deviation 2.3 in. The survey also found that​ men's heights are normally distributed with a mean 69.1 in. and standard deviation 2.9. Complete parts a through c below. a. Most of the live characters at an amusement park have height requirements with a minimum of 4 ft 9 in. and a maximum of 6 ft 2 in. Find the percentage of women meeting the height requirement. The percentage of women who meet the height requirement is nothing ​%. ​(Round to two decimal places as​ needed.)

Answer 1

As 1 foot = 12 inches So 4 ft 9 in = 45 in and 6 ft 2 in = 74 in

Define the standard random variable Z as where X denotes the height of women

Then using normal table we have

Hence,  percentage of women meeting the height requirement is 99.85%