5. Let p be the proportion of the population who respond yes.
a) In a survey of 700 US adults, 118 felt that alcoholism was a reasonable excuse for criminal conduct. Use the information to find p-hat & q-hat.
b) Find the maximum error of estimate for p, with a 93% confidence level (assume normally distributed).
c) Find the confidence interval with a 93% confidence level.
here x=118 n=700
p^=x/n=118/700=0.1686
q^=1-p^=1-0.1686=0.8314
Ansb:
ME=maximum error of estimate for p
AT 93 % CI the value of z is 1.8119
ME=Z*sqrt(p^*q^/n)
=1.8119*sqrt(0.1686*0.8314/700)
=0.0256
Ansc:
confidence interval with a 93% confidence level. is
(p^-ME,p^+ME)
(0.1686-0.0256,0.1686+0.0256)
(0.143,0.194)
5. Let p be the proportion of the population who respond yes. a) In a survey...
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