Question

An insurance company wants to know the proportion of clients who have had claims within the last year. They randomly select 1

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Answer - 1: np = 100*0.05 = 5 which is less than 10. Hence,

Option C is correct.

Answer - 2: This was a voluntary response sample so it is not random.

Option B is correct.

Add a comment
Know the answer?
Add Answer to:
An insurance company wants to know the proportion of clients who have had claims within the...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A university officer wants to know the proportion of registered students that spend more than 20...

    A university officer wants to know the proportion of registered students that spend more than 20 minutes to get to school. He selects two parking decks at the university and talked with students at those decks. Of 25 students found in the decks, 12 have a commute under 20 minutes and 13 have a commute more than 20 minutes. Select one: THIS IS A MULTIPLE CHOICE QUESTION a. Yes. b. No, because it wasn't a random sample. c. No, because...

  • For the following four questions, is it appropriate to use a normal distribution to approximate a...

    For the following four questions, is it appropriate to use a normal distribution to approximate a confidence interval for the population proportion? If it’s inappropriate, indicate why. A clothing store owner wants to know the proportion of customers who used coupons within the last year. He selects in a random order all 2,000 receipts from a database of all purchases within the last year and finds that 340 of them are discounted by coupons. Select one: a. Yes. b. No,...

  • A market researcher wants to conduct a survey to estimate the population proportion who prefer Coca-Cola...

    A market researcher wants to conduct a survey to estimate the population proportion who prefer Coca-Cola to Pepsi. Before conducting the survey, the researcher wants to choose a sample size so that the half width of the 99% confidence interval is no more than 2%, regardless what he will find. What is the required sample size? Hints: recall that we only deal with "large n" population proportion questions in the class, so use the Z distribution. Also recall that the...

  • A market researcher wants to conduct a survey to estimate the population proportion who prefer Coca-Cola...

    A market researcher wants to conduct a survey to estimate the population proportion who prefer Coca-Cola to Pepsi. Before conducting the survey, the researcher wants to choose a sample size so that the half width of the 99% confidence interval is no more than 2%, regardless what he will find. What is the required sample size? Hints: recall that we only deal with "large n" population proportion questions in the class, so use the Z distribution. Also recall that the...

  • The following 5 questions are based on this information. The proportion of headache sufferers who get...

    The following 5 questions are based on this information. The proportion of headache sufferers who get relief with just two aspirins is 53% (p = 0.53). We plan to take a random sample of 400 headache sufferers. The sampling distribution of is Select one: a. not normal because the sample size is too small O b. not normal because np < 5 O c. normal because np < 5 and n(1 – p) < 5 O d. normal because np...

  • a)A university planner wants to determine the proportion of spring semester students who will attend summer...

    a)A university planner wants to determine the proportion of spring semester students who will attend summer school. Suppose the university would like a 0.90 probability that the sample proportion is within 0.195 or less of the population proportion.What is the smallest sample size to meet the required precision? (There is no estimation for the sample proportion.)  (Enter an integer number.) b)A university planner wants to determine the proportion of spring semester students who will attend summer school. She surveys 31 current...

  • An auditor wants to know the (population) proportion (p) of companies under audit that may have...

    An auditor wants to know the (population) proportion (p) of companies under audit that may have financial distress. Before she starts to collect data, she needs to determine the sample size (n) in the random sample that she is going to take. If the auditor wants to be 95% confident that the maximum difference between the unbiased point estimator and pto be 0.02, determine nif she has no prior knowledge about p; her prior knowledge about pfrom the previous three...

  • C (0.331, 0.400) 21) In the months leading up to an election, news organizations conduct many...

    C (0.331, 0.400) 21) In the months leading up to an election, news organizations conduct many surveys to help predict the results of the election. Often news organizations will increase the sample size in the last few weeks before the election. Which of the following is the primary reason they increase the sample size? Alarger sample size allows more people to give their input. . Alarger sample size means the sampling method isn't as important. C A larger sample size...

  • Question Help * A television sports commentator wants to estimate the proportion of citizens who "follow...

    Question Help * A television sports commentator wants to estimate the proportion of citizens who "follow professional football." Complete parts (a) through (c). (a) What sample size should be obtained if he wants to be within 2 percentage points with 95% confidence if he uses an estimate of 48% obtained from a poll? The sample size is(Round up to the nearest integer) (b) What sample size should be obtained if he wants to be within 2 percentage points with 95%...

  • 9.1.45-1 Jane wants to estimate the proportion of students on her campus who eat cauliflower. After...

    9.1.45-1 Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 39 students, she finds 4 who eat cauliflower. Obtain and interpret a 90% confidence interval for the proportion of students who eat cauliflower on Jane's campus using Agresti and Coull's method. - Click the icon to view Agresti and Coull's method. Construct and interpret the 90% confidence interval. Select the correct choice below and fill in the answer boxes within your choice. (Round...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT