A student wishes to titrate a solution of glycine.HCl with a 0.1000 M solution of NaOH...
A student wishes to titrate a solution of glycine.HCl with a 0.1000 M solution of NaOH using a 50-mL buret. If the student desires the second equivalence to occur at approximately 30. mL of titrant, what mass of glycine.HCl should be dissolved in water for the titration?
Homework Answers
To obtain the second point of equivalence at 30 mL, the first point of equivalence at 15 mL was obtained, the required mass of glycine-HCl is calculated:
m glycine-HCl = M * V * MM = 0.1 M * 0.015 L * 111.53 g / mol = 0.167 g
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