Calculate the molar solubility and solubility in grams/liter for Copper(I) iodide
Ksp CuI = 1.27 x 10-12
CuI (s) Cu+ (aq) + I- (aq)
Let molar solubility of CuI be 's'
[Cu+] = s
[I-] = s
Ksp CuI = [Cu+][I-]
1.27 x 10-12 = (s) * (s)
s2 = 1.27 x 10-12
s = (1.27 x 10-12)1/2
s = 1.13 x 10-6 M
Molar solubility of CuI = s = 1.13 x 10-6 M
solubility = (molar solubility) * (molar mass CuI)
solubility = (1.13 x 10-6 M) * (190.45 g/mol)
solubility = 2.15 x 10-4 g/L
Calculate the molar solubility and solubility in grams/liter for Copper(I) iodide
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