How much heat is required to raise the temperature of 60 grams of water from 25-degrees Celsius to 85 degrees Celcius?
specific heat of water is 4.187 kJ/kgK.
∆t = 85℃-25℃ = 60℃
m = 60g = 0.060 kg
This means 4.187 kJ will raise the temperature of 1 Kg water 1
degree K (= 1 degree C)
you need to raise 0.06 Kg water 60 degrees.
i.e (85℃-25℃ = 60℃)
∆E = mc∆t
=60℃ x 0.060 Kg x 4.187 kJ / Kg degree = 15.1 kJ......Answer.
Hope this helps.
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