A December 2013 Gallup poll of 13,186 nationally representative adults found that 8.9% reported being sick...
Homework Answers
Answer:
Given,
Sample n = 13186
p = 8.9%
Here at 95% CI, z value = 1.96
Interval = p +/- z*sqrt(pq/n)
substitute values
= 0.089 +/- 1.96*sqrt(0.089(1-0.089)/13186)
= 0.089 +/- 0.0049
= (0.0841 , 0.0939)
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