a)
Level of Significance, α = 0.05
Sample Size, n = 1000
Sample Proportion , p̂ = 0.61
z -value =Z0.05/2= 1.9600
Standard Error , SE = √[p̂(1-p̂)/n] =
0.0154
margin of error , E = Z*SE = 0.0302
Confidence Interval
Interval Lower Limit , = p̂ - E =
0.5798
Interval Upper Limit , = p̂ + E =
0.6402
confidence interval is(0.58,0.64)
b)
yes,it would be a surprising result,as true percentage is
outside the confidence interval
A newspaper reported on the results of an opinion poll in which adults were asked what...
A newspaper reported on the results of an opinion poll in which adults were asked what one thing they are most likely to do when they are home sick with a cold or the flu. In the survey, 62% said that they are most likely to sleep and 17% said that they would watch television. Although the sample size was not reported, typically opinion polls include approximately 1,000 randomly selected respondents a. Assuming a sample size of 1,000 for this...
A newspaper reported on the results of an opinion poll in which adults were asked what one thing they are most likely to do when they are home sick with a cold or the flu. In the survey, 64% said that they are most likely to sleep and 13% said that they would watch television. Although the sample size was not reported, typically opinion polls include approximately 1,000 randomly selected respondents. a. Assuming a sample size of 1,000 for this...
A newspaper reported on the results of an opinion poll in which adults were asked what one thing they are most likely to do when they are home sick with a cold or the flu. In the survey, 60% said that they are most likely to sleep and 12% said that they would watch television. Although the sample size was not reported, typically opinion polls include approximately 1,000 randomly selected respondents. a. Assuming a sample size of 1,000 for this...
A newspaper reported on the results of an opinion poll in which adults were asked what one thing they are most likely to do when they are home sick with a cold or the flu. In the survey, 60% said that they are most likely to sleep and 11% said that they would watch television. Although the sample size was not reported, typically opinion polls include approximately 1,000 randomly selected respondents. a. Assuming a sample size of 1,000 for this...
A newspaper reported on the results of an opinion poll in which adults were asked what one thing they are most likely to do when they are home sick with a cold or the flu. In the survey, 65% said that they are most likely to sleep and 12% said that they would watch television. Although the sample size was not reported, typically opinion polls include approximately 1,000 randomly selected respondents. a. Assuming a sample size of 1,000 for this...
USA Today (Feb 15. 2007) reported on the results of an opinion poll in which adults were asked what one thing they are most likely to do when they are home sick with a cold or the flu. In the survey, 63% said that they are most likely to sleep and 18% said they would watch television. Although the sample size was not reported, typically opinion polls include approximately 1,000 randomly selected respondents. (a) Assuming a sample size of 1,000...
A poll taken this year asked 1009 adults whether they were fans of a particular sport and 55% said they were. Last year, 56% of a similar-size sample had reported being fans of the sport. a) Find the margin of error for the poll taken this year if one wants 90% confidence in the estimate of the percentage of adults who are fans of the sport. b) If one wanted to be 85% confident instead of 90% confident, would the...
In a recent poll of 1 adults current debt during the next three months. A more detailed poll surveyed 1288 adult groups, 18-29, 30-49, 50-64, and 65+. Complete parts a and b below ) Do you expect the 95% confidence interval for the true proportion of all 18-to 29-year-olds who are wormed to be wider or narrower than the 95% c for the true proportion of all consumers? Explain Choose the correct answer below O A The interval for the...
A December 2013 Gallup poll of 13,186 nationally representative adults found that 8.9% reported being sick with a cold. Based on these results, what is a 95% confidence interval for the proportion p of American adults who were sick with a cold that month?
11: In a Gallup poll of 1000 randomly selected adults, 347 of them said they were underpaid. Construct a 95% confidence interval estimate of the percentage (proportion) of all adults who say that they are underpaid. Round to the nearest hundredth. 12: If you are using a ? −test when testing a claim about a population mean and the sample size is 53, the number of degrees of freedom is ________.