When parking a car in a downtown parking lot, drivers pay according to the number of hours or fraction thereof. The probability distribution of the number of hours cars are parked has been estimated as follows:
X | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
P(X) | 0.224 | 0.142 | 0.106 | 0.08 | 0.057 | 0.039 | 0.033 | 0.319 |
A. Mean =
B. Standard Deviation =
The cost of parking is 2.25 dollars per hour. Calculate the mean and standard deviation of the amount of revenue each car generates.
A. Mean =
B. Standard Deviation =
Answer
(A)Mean =
using the data table
And
(B)Standard deviation =
x(bar) is mean = 4.448, P(X) is probability and X is the given values in the data table
this implies
The cost of parking is 2.25 dollars per hour
(A) mean =
= 4.448*2.25
= $10.008
(B) Standard deviation =
= 8.10*2.25
= $18.225
When parking a car in a downtown parking lot, drivers pay according to the number of...
When parking a car in a downtown parking lot, drivers pay according to the number of hours or fraction thereof. The probability distribution of the number of hours cars are parked has been estimated as follows: X12345678P(X)0.2130.1170.120.0850.0620.0280.0230.352A. Mean = _______ B. Standard Deviation = _______ The cost of parking is 3.25 dollars per hour. Calculate the mean and standard deviation of the amount of revenue each car generates A. Mean = _______ B. Standard Deviation = _______
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