How would you prepare 425 g of an aqueous solution containing 2.40% by mass of sodium acetate, NaC2H3O2?
425 g aqueous solution = sodium acetate + water
According to the question, sodium acetate present 2.40 % by mass. It means 100 g aqueous solution contain 2.40 g of sodium acetate and 97.60 g of water.
Since 100 g solution contain = 2.40 g of sodium acetate
1 g solution contain = 2.40 g/100 = 0.0240 g
425 g solution contain = 0.0240 g × 425 = 10.2 g of sodium acetate
Therefore mass of water required = 425 g - 10.2 g = 414.8 g
Conclusion : 425 g of aqueous solution prepared by dissolving 10.2 g of sodium acetate in 414.8 g of water.
How would you prepare 425 g of an aqueous solution containing 2.40% by mass of sodium...
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