You have a large inventory of Intel processors that run at 3 GHz and 1 Volt, and consume 100 W (of which, 20 W is leakage) when running a given CPU-bound application. This application finishes in 100 seconds on this processor. The processor is capable of DFS and DVFS, but cannot reduce its voltage under 0.9 V. A customer places an order for motherboards that have inexpensive cooling and power delivery that can only handle a processor that runs at 40 W. How will you configure your Intel processor so that it meets these specifications and consumes as little energy as possible for the same CPU-bound application? How much energy does the processor consume to finish this application on this new system?
Solution
v=voltage
f=frequency
Leakage Power=20W
Dynamic Power=80W.
Leakage Power = v * c
Dynamic Power = activity * capacity * v2 * f
In order to the have the least power, we set the new voltage to 0.9V
New Leakage Power
= 20W * 0.9
= 18W
New Dynamic Power
= 80W*0.92 * new f/old f
= 40W – 18W
= 22W
So we configure the processor that new frequency is 1.02 GHz, new voltage is 0.9V to meet the specification and consumes as little energy as possible.
New time = 100 * old f / new f
= 294.11
So
the total energy
= New time * power
= 40W * 294.11
= 11764.7J
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