Galvimetric determination of iron Fe2O3.A precipitate of Fe(OH)3 (s) is contaminated with Ca(OH)2 (s). Explain how one can get rid of the contamination.
Galvimetric determination of iron Fe2O3.A precipitate of Fe(OH)3 (s) is contaminated with Ca(OH)2 (s). Explain how...
A precipitate of Fe(OH)3 is contaminated with Mg(OH)2. Explain how to can get rid of the contamination.
The reaction of iron ore with carbon follows the equation: 2 Fe2O3+ 3 C 4 Fe+3 CO2 3. How many grams of Fe can be produced from a mixture of 200 g of Fe2O3 and 300. g of C?
4 Fe(s) + 3 O2(g) → 2 Fe2O3(s) AH = -1652 kJ (a) How much heat is released when 3.54 mol iron are reacted with excess O2? Ok] (b) How much heat is released when 1.48 mol Fe2O3 is produced? CJ) (c) How much heat is released when 2.50 g iron are reacted with excess O2? DJ (d) How much heat is released when 12.6 g Fe and 1.02 g O2 are reacted? CkJ
The following reaction is at equilibrium: 2 Fe(OH)3(s) ↔ Fe2O3(s) + 3 H2O(g); Ho > 0. Which of the following changes will result in a decrease in the concentration of water (gas)? 1. Increasing the temperature. 2. Decreasing pressure. 3. Adding a catalyst. 4. Adding some Fe(OH)3. 5. Decreasing the volume. 6. Removing some Fe2O3.
Iron(III) oxide reacts with carbon to give iron and carbon monoxide: Fe2O3(s)+3C(s)→2Fe(s)+3CO(g) Question: How many grams of Fe can be produced when 6.10 g of Fe2O3 reacts?
Iron(III) oxide reacts with carbon to give iron and carbon monoxide. Fe2O3(s)+3C(s)→2Fe(s)+3CO(g) How many grams of C are required to react with 29.0 g of Fe2O3? How many grams of CO are produced when 41.0 g of C reacts? How many grams of Fe can be produced when 6.20 g of Fe2O3 reacts?
part 1 of 3 Iron is generally produced from iron ore through the reaction Fe2O3(s) + CO(g) −→ Fe(s) + CO2(g) . If 3.3 kg of Fe2O3 are available to react, how much CO is needed? 1. 54.4771 2. 95.8046 3. 105.197 4. 46.9631 5. 20.6637 6. 110.833 7. 61.9912 8. 33.8134 9. 73.2624 10. 65.7483 015 (part 2 of 3) 10.0 points How much Fe can be produced? 1. 53.851 2. 57.608 3. 16.2805 4. 62.6174 5. 72.6362 6....
b Using the equation: Fe2O3(s) + 3 CO(g) + 2 Fe(s) + 3 CO2(g) How many moles of Fe2O3 are required to produce 45.9 mol of Fe? How many grams of CO are required to produce 45.9 mol of Fe? 1 pt nFe2O3) - mol 1 pt m(CO) -
Classify the following as acid-base reactions or oxidation-reduction reactions. (a) 3 HClO4(aq) + Fe(OH)3(s) → Fe(ClO4)3(aq) + 3 H2O(l) (b) HC2H3O2(aq) + NaHCO3(aq) → NaC2H3O2(aq) + CO2(g) + H2O(l) (c) 4 H2O(l) + 2 KMnO4(aq) → 2 MnO2(s) + 2 KOH(aq) + 3 H2O2(aq) (d) Cl2(g) + KOH(aq) → KClO(aq) + HCl(aq) (e) 2 Fe(s) + 3 NaOCl(aq) → Fe2O3(s) + 3 NaCl(aq) (f) CaC2(s) + 2 H2O(l) → C2H2(g) + Ca(OH)2(s) Explain your reasoning
How many kg of iron (Fe) is needed to produce -9.232x104 kJ heat: 4 Fe(s) + 3 O2(g) --> 2 Fe2O3(s) DHrxn = -1.65 x 103 kJ A: 10.43 kg B: 12.50 kg C: 25.00 kg D: 2341 kg