Question

b Using the equation: Fe2O3(s) + 3 CO(g) + 2 Fe(s) + 3 CO2(g) How many moles of Fe2O3 are required to produce 45.9 mol of Fe? How many grams of CO are required to produce 45.9 mol of Fe? 1 pt nFe2O3) - mol 1 pt m(CO) -

Answer 1

- Given equation → Fee Oz (3). + 300(3) -→ ? Fe(s) + 36,4) From the above balanced equation, one mole of Fee Oo (s) reacts with three moles of co to produce 2 moles of Fe(s) and 3 moles of CO₂ (gl. We need to pauduse .459 mol of Fe 3 mole of co produces a mole of Fe (8) I mole of Fe (1) are produce from 3 mol of co - 45 9 mol of Te() is produced from a Ź * ???mel = 68.85 mol of co. 20

co = 28 x 6885 e. 1 mol of co = 28 gm of co 68°85 mol of CO = 28 x 6885.g of co - 1827.8 g of co m[60) 192786 I mel of Felix G) produces 2 mol of Fe (3) I mol of Fe G is produced from : & mol of *2 Fee Oly) 4519 mol of Feb) j_prodved from ; 0 m x 45.9 mol 22.95 mol n / Fee Os) = 22.15 mola