How many miles of Fe2O3 are required to produce 41.2 mol of Fe? How many grams of CO are required to produce 41.2 mol of Fe?
Please show the math
The reaction will be
As per the balanced reaction, one mole of Fe2O3 will produce 2 moles of Fe
Moles of Fe2O3 needed = 1/2 * number of moles of Fe = 1/2 * 41.2 = 20.6
As per the balanced reaction, three mole of CO will produce 2 moles of Fe
Moles of CO needed = 3/2 * number of moles of Fe = 3/2 * 41.2 = 61.8 moles
Molar mass of CO = Molar mass of C + Molar mass of O = 12 + 16 = 28 g/mol
Grams of CO needed = (number of moles) * molar mass = 61.8 mol * 28 gm/mol = 1730.4 grams
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