Question

How many miles of Fe2O3 are required to produce 41.2 mol of Fe? How many grams...

How many miles of Fe2O3 are required to produce 41.2 mol of Fe? How many grams of CO are required to produce 41.2 mol of Fe?

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Answer #1

The reaction will be

Fe2O3 + 3C0 + 2Fe +3CO,

As per the balanced reaction, one mole of Fe2O3 will produce 2 moles of Fe

Moles of Fe2O3 needed = 1/2 * number of moles of Fe = 1/2 * 41.2 = 20.6

As per the balanced reaction, three mole of CO will produce 2 moles of Fe

Moles of CO needed = 3/2 * number of moles of Fe = 3/2 * 41.2 = 61.8 moles

Molar mass of CO = Molar mass of C + Molar mass of O = 12 + 16 = 28 g/mol

Grams of CO needed = (number of moles) * molar mass = 61.8 mol * 28 gm/mol = 1730.4 grams

Note - Post any doubts/queries in comments section.

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