How many grams of iron is in 6.42 × 10E-2 mol Fe?
Mass of 1 mole of Fe = 55.845 g
mass of 6.42*10^-2 mole of Fe =
= 6.42*10^-2 mole of Fe *(55.845 g / 1 mole of Fe)
= 359 * 10^-2 g
= 3.59 g
Therefore, the mass of 6.42*10^-2 mole of Fe = 3.59 g
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