Question

MATLAB Onramp ASSIGNMENT:

2. Create a 1x15 (1 row, 10 columns) vector of random numbers (use randn command “x = randn(1,10)). And do the following:

a.Test vector x for elements that are less than 0.2. Assign the output to a variable named y.

b.Create a variable z that contains the elements in x that are greater than 0.2.

c. Modify vector x such that any value in it less than 0.2 is replaced by value 0.

Answer 1

  MATLAB CODE

clc;
x=randn(1,10); % Random x matrix
z=[]; % Initilise z matrix
y=[]; % Initilise z matrix
i_z=1; % Staring index for z matrix
i_y=1; % Staring index for y matrix
disp('Initial x matrix is ')
disp(x);

for i=1:10
if(x(i)>0.2) % for x[i] >0.2
z(i_z)=x(i);
i_z=i_z+1; % Increase iterator(index) for y matrix
end
if(x(i)<0.2)
y(i_y)=x(i);
i_y=i_y+1; % Increase iterator(index) for y matrix
x(i)=0; % updating x for x(i)<0.2 as 0
end
end
disp('y matrix is ');
disp(y);
disp('z matrix is ');
disp(z);
disp('New x matrix is ');
disp(x);
  

RESULT:

Initial x matrix is
-1.3499 3.0349 0.7254 -0.0631 0.7147 -0.2050 -0.1241 1.4897 1.4090 1.4172
y matrix is
-1.3499 -0.0631 -0.2050 -0.1241
z matrix is
3.0349 0.7254 0.7147 1.4897 1.4090 1.4172
New x matrix is
0 3.0349 0.7254 0 0.7147 0 0 1.4897 1.4090 1.4172
>>