Create a Latin square design with p=5 (No replication) using the pattern below B C D...
Create a Latin square design with p=5 (No replication) using the pattern below
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E |
A |
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C |
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D |
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___ |
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E |
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A |
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What is the degrees of freedom associated with error in Latin square design specified above?
use R language to run the test
Homework Answers
| B | C | D | E | A |
| C | D | E | A | B |
| D | E | A | B | C |
| E | A | B | C | D |
| A | B | C | D | E |
For, i = 1, ... , t ; j = 1, ... , t
Degrees of freedom associated with error is (t-1)*(t-2) i.e 4*4 = 16 in our case.
Add Answer to:
Create a Latin square design with p=5 (No
replication)
using
the pattern below
B
C
D...
30. An experiment was conducted using a fixcd cffeets 5 x 5 Latin square design. Which...
30. An experiment was conducted using a fixcd cffeets 5 x 5 Latin square design. Which of the following statements is FALSE? (b) The total number of ohservations for this experiment is 25. (e) MSSSE (d) MScuS 12
(a) fill the blank (a),(b),(c),(d), and (e) (b) which model has small test error? justify your...
(a) fill the blank (a),(b),(c),(d), and (e)
(b) which model has small test error? justify your
answer
(c) compute AIC values for two models. Which model has smaller
test error ?
(d) to use F-test, find a F statistic value and degree of
freedom for the test
Model 1 (MI): Call: 1m(formula = Y - X1 + X2 + factor (X3) Coefficients: Estimate Std. Error t value (Intercept) 7.1745 4.8418 1.482 0.8049 0.2522 3.192 X2 0.6281 0.2460 2.553 factor (X3)B...
a) true b) false 42. For a chi-square distributed random variable with 10 degrees of freedom and a level of sigpificanoe computed value of the test statistics is 16.857. This will lead us to reje...
a) true b) false 42. For a chi-square distributed random variable with 10 degrees of freedom and a level of sigpificanoe computed value of the test statistics is 16.857. This will lead us to reject the null hypothesis. a) true b) false 43. A chi-square goodness-of-fit test is always conducted as: a. a lower-tail test b. an upper-tail test d. either a lower tail or upper tail test e. a two-tail test 44. A left-tailed area in the chi-square distribution...
Given are five observations for two variables, r and y. 3 4 5 1 2 7 6 11 14 4 The estimated regression equation is...
Given are five observations for two variables, r and y. 3 4 5 1 2 7 6 11 14 4 The estimated regression equation is y = 1.2 + 2.4r Compute the mean square error using the following equation (to 3 decimals). a. SSE s2=MSE n- 2 decimals). b. Compute the standard error of the estimate using the following equation (to SSE VMSE Vn-2 SE c. Compute the estimated standard deviation bi using the following equation (to 3 decimals). Sp...
b and d are correct (1 point) Suppose you are using a completely randomized design to...
b and d are correct
(1 point) Suppose you are using a completely randomized design to study some phenomenon. There are Afive treatment levels and a total of 55 people in the study. Each treatment level has the same sample size. (a) Complete the following ANOVA table. P-value Source Degrees of Freedom Treatment 1 : Sum of Squares 583.39 Mean Square 583.39 18.343 31.804 00 Error 53 !! 972.18 ! Total 54 1555.57 (b) Formulate the appropriate statistical hypotheses. A....
Please help me answer this question for my Statistical Methods subject. PLEASE answer it seriously and completely, or be...
Please help me answer this question for my Statistical Methods
subject. PLEASE answer it seriously and completely, or better not
answer it if not then, really appreciate it, thank you.
5 (a) An incomplete result of summarized in the analysis of variance table below. experiment using Latin square design is an Source of Degrees of Sum of Mean Variation Squares Freedom Squares Treatments 7 58.25 Rows 17.25 7 38.25 Columns Error 6.5 Total 7 State the size of the Latin...
5. A randomized block design is used in an experiment. There are 4 treatments and 3...
5. A randomized block design is used in an experiment. There are 4 treatments and 3 blocks. Use the information below to complete the table. b a b a (*; – x)² = 50 {(xy - x)= 712 (#4 - 3)2 = 98 i=1 j=1 i= Degrees of Freedom Sum of Squares Mean Square f P value Source of Variation Treatments Blocks Error Total
#16 The test statistic is a. 6.00. b. 2.25. c. 3.00. d. 2.67. #17 The mean...
#16
The test statistic is
a.
6.00.
b.
2.25.
c.
3.00.
d.
2.67.
#17
The mean square due to error (MSE) is
a.
60.
b.
18.
c.
15.
d.
20.
Part of an ANOVA table is shown below. Sum of Degrees Squares Freedom Mean of Source of Variation Square 180 Between Treatments Within Treatments (Error) TOTAL 480 18
Given the State Table Below 01 02 Q3 X-1 A. B. C. Draw a state Diagram (S points) Create the "design truth table" for the "next state" and the "output" (5 points) Make...
Given the State Table Below 01 02 Q3 X-1 A. B. C. Draw a state Diagram (S points) Create the "design truth table" for the "next state" and the "output" (5 points) Make a Karnaugh for each "next state" and the "output" (10 points) When making the Karnaugh maps, "xQ1" should be along the top and "O203" along the side (The two missing states should be considered "DONT CARES") Write the "Next State" and Output equations from the Karnaugh maps...
Create C++ program.Convert this string to Tap Code using structures. It is very important to use structures in this program. The tap code is based on a Polybius square using a 5×5 grid of letters repr...
Create C++ program.Convert this string to Tap Code using structures. It is very important to use structures in this program. The tap code is based on a Polybius square using a 5×5 grid of letters representing all the letters of the Latin alphabet, except for K, which is represented by C. The listener only needs to discriminate the timing of the taps to isolate letters. Each letter is communicated by tapping two numbers the first designating the row (Down) the...
30. An experiment was conducted using a fixcd cffeets 5 x 5 Latin square design. Which of the following statements is FALSE? (b) The total number of ohservations for this experiment is 25. (e) MSSSE (d) MScuS 12
(a) fill the blank (a),(b),(c),(d), and (e)
(b) which model has small test error? justify your
answer
(c) compute AIC values for two models. Which model has smaller
test error ?
(d) to use F-test, find a F statistic value and degree of
freedom for the test
Model 1 (MI): Call: 1m(formula = Y - X1 + X2 + factor (X3) Coefficients: Estimate Std. Error t value (Intercept) 7.1745 4.8418 1.482 0.8049 0.2522 3.192 X2 0.6281 0.2460 2.553 factor (X3)B...
a) true b) false 42. For a chi-square distributed random variable with 10 degrees of freedom and a level of sigpificanoe computed value of the test statistics is 16.857. This will lead us to reject the null hypothesis. a) true b) false 43. A chi-square goodness-of-fit test is always conducted as: a. a lower-tail test b. an upper-tail test d. either a lower tail or upper tail test e. a two-tail test 44. A left-tailed area in the chi-square distribution...
Given are five observations for two variables, r and y. 3 4 5 1 2 7 6 11 14 4 The estimated regression equation is y = 1.2 + 2.4r Compute the mean square error using the following equation (to 3 decimals). a. SSE s2=MSE n- 2 decimals). b. Compute the standard error of the estimate using the following equation (to SSE VMSE Vn-2 SE c. Compute the estimated standard deviation bi using the following equation (to 3 decimals). Sp...
b and d are correct
(1 point) Suppose you are using a completely randomized design to study some phenomenon. There are Afive treatment levels and a total of 55 people in the study. Each treatment level has the same sample size. (a) Complete the following ANOVA table. P-value Source Degrees of Freedom Treatment 1 : Sum of Squares 583.39 Mean Square 583.39 18.343 31.804 00 Error 53 !! 972.18 ! Total 54 1555.57 (b) Formulate the appropriate statistical hypotheses. A....
Please help me answer this question for my Statistical Methods
subject. PLEASE answer it seriously and completely, or better not
answer it if not then, really appreciate it, thank you.
5 (a) An incomplete result of summarized in the analysis of variance table below. experiment using Latin square design is an Source of Degrees of Sum of Mean Variation Squares Freedom Squares Treatments 7 58.25 Rows 17.25 7 38.25 Columns Error 6.5 Total 7 State the size of the Latin...
5. A randomized block design is used in an experiment. There are 4 treatments and 3 blocks. Use the information below to complete the table. b a b a (*; – x)² = 50 {(xy - x)= 712 (#4 - 3)2 = 98 i=1 j=1 i= Degrees of Freedom Sum of Squares Mean Square f P value Source of Variation Treatments Blocks Error Total
#16
The test statistic is
a.
6.00.
b.
2.25.
c.
3.00.
d.
2.67.
#17
The mean square due to error (MSE) is
a.
60.
b.
18.
c.
15.
d.
20.
Part of an ANOVA table is shown below. Sum of Degrees Squares Freedom Mean of Source of Variation Square 180 Between Treatments Within Treatments (Error) TOTAL 480 18
Given the State Table Below 01 02 Q3 X-1 A. B. C. Draw a state Diagram (S points) Create the "design truth table" for the "next state" and the "output" (5 points) Make a Karnaugh for each "next state" and the "output" (10 points) When making the Karnaugh maps, "xQ1" should be along the top and "O203" along the side (The two missing states should be considered "DONT CARES") Write the "Next State" and Output equations from the Karnaugh maps...
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