Question

How much money do people spend on graduation gifts? In 2007, a federation surveyed 2815 consumers...

How much money do people spend on graduation gifts? In 2007, a federation surveyed 2815 consumers who reported that they bought one or more graduation gifts that year. The sample was selected in a way designed to produce a sample representative of adult Americans who purchased graduation gifts in 2007. For this sample, the mean amount spent per gift was $52.65. Suppose that the sample standard deviation was $20. Construct a 98% confidence interval for the mean amount of money spent per graduation gift in 2007. (Round your answers to three decimal places.)

0 0
Add a comment Improve this question Transcribed image text
Answer #1
sample mean 'x̄= 52.650
sample size   n= 2815.00
sample std deviation s= 20.000
std error 'sx=s/√n= 0.3770
for 98% CI; and 2814 df, value of t= 2.328
margin of error E=t*std error    = 0.877
lower bound=sample mean-E = 51.773
Upper bound=sample mean+E = 53.527
from above 98% confidence interval for population mean =(51.773 ,53.527)
Add a comment
Know the answer?
Add Answer to:
How much money do people spend on graduation gifts? In 2007, a federation surveyed 2815 consumers...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • PART 1 31 people were surveyed and reported the amount of money they spend on a...

    PART 1 31 people were surveyed and reported the amount of money they spend on a typical date night. The results were roughly bell-shaped with a mean of $35 and standard deviation of $20. Construct a confidence interval at a 98% confidence level. Give your answers to two decimal places. PART 2 A variable x is normally distributed with mean 19 and standard deviation 6. Round your answers to the nearest hundredth as needed. a) Determine the z-score for x=29....

  • A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for...

    A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for a random sample of 1087 people age 15 or​ older, the mean amount of time spent eating or drinking per day is 1.21 hours with a standard deviation of 0.52 hour. Determine and interpret a 99​% confidence interval for the mean amount of time Americans age 15 or older spend eating and drinking each day. A.The nutritionist is 99​% confident that the mean amount...

  • A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for...

    A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for a random sample of 1031 people age 15 or​ older, the mean amount of time spent eating or drinking per day is 1.14 hours with a standard deviation of 0.56 hour. Determine and interpret a 90​% confidence interval for the mean amount of time Americans age 15 or older spend eating and drinking each day.

  • A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for...

    A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for a random sample of 943 people age 15 or older the mean amount of time spent eating or drinking per day is 1.35 hours with a standard deviation of 0.74 hour. Determine and interpret a 99% confidence interval for the mean amount of time Americans age 15 or older spend eating and drinking each day. Select the correct choice below and fill in the...

  • A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for...

    A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for a random sample of 1069 people age 15 or​ older, the mean amount of time spent eating or drinking per day is 1.36 hours with a standard deviation of 0.67 hour. a) A histogram of time spent eating and drinking each day is skewed right. Use this result to explain why a large sample size is needed to construct a confidence interval for the...

  • A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for...

    A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for a random sample of 993 people age 15 or​ older, the mean amount of time spent eating or drinking per day is 1.45 hours with a standard deviation of 0.55 hour. Complete part (c) (c) Determine and interpret a 90​% confidence interval for the mean amount of time Americans age 15 or older spend eating and drinking each day. Select the correct choice below...

  • A nutritionis wants to determine how much time onally people spend eating and drinking Suppose for...

    A nutritionis wants to determine how much time onally people spend eating and drinking Suppose for a random sample of 913 people age 15 or older the mean amount of time spent eating or drinking per day is 174 hours wit a standard deviation of 65 hour Complete parts (al through (d) below. (a) A histogram of time sport eating and drinking each day is skewed Use this result to explain why a large sample size is needed to construct...

  • Solve the problem. How much money does the average professional football fan spend on food at...

    Solve the problem. How much money does the average professional football fan spend on food at a single football game? That question was posed to 10 randomly selected football fans. The sample results provided a sample mean and standard deviation of $19.00 and $2.95, respectively. Use this information to construct a 98% confidence interval for the mean.

  • A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for...

    A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for a random sample of 982982 people age 15 or​ older, the mean amount of time spent eating or drinking per day is 1.181.18 hours with a standard deviation of 0.550.55 hour. Complete parts ​(a) through ​(d) below. ​(a) A histogram of time spent eating and drinking each day is skewed right. Use this result to explain why a large sample size is needed to...

  • Thank you in advance! A nutritionist wants to determine how much time nationally people spend eating...

    Thank you in advance! A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for a random sample of 961 people age 15 or older, the mean amount of time spent eating or drinking per day is 1.86 hours with a standard deviation of 0.64 hour. Complete parts (a) through (d) below. 0 A. The sample size is greater than 10% of the population B. The sample size is less than 10% of the population....

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT