An ideal transformer has 4500. turns in its primary (input) and 14500. turns in its secondary...

Question

Question

An ideal transformer has 4500. turns in its primary (input) and 14500. turns in its secondary...

An ideal transformer has 4500. turns in its primary (input) and 14500. turns in its secondary (output). 10.0-V ac is connected to the primary (input).

a) What is the voltage on the secondary (output)?

b) What is the secondary (output) current if an 8.00-Ω resistor is connected to the secondary (output)?

c) What is the power supplied to the primary (input)?

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Answer 1

Answer #1

a)

N_p = number of turns in primary= 4500

N_s = number of turns in secondary = 14500

V_p = primary Ac Voltage = 10 volts

V_s = secondary voltage

Using the equation

V_s /V_p = N_s /N_p

V_s /10 = 14500/4500

V_s = 32.2 Volts

b)

R_s = resistance connected to secondary side = 8 ohm

i_s = current on secondary side

Using ohm's law

V_s = i_s R_s

32.2 = i_s (8)

i_s = 4.025 A

c)

i_p = current in primary side

Using the equation

i_p/i_s = V_s/V_p

i_p/4.025 = 32.2/10

i_p = 12.96 A

P = Power in primary side = i_p V_p = 12.96 x 10 = 129.6 Watt

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Answer 2

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