Question

Given the following linear program that maximizes revenue (assume x and y cannot be negative): Max...

  1. Given the following linear program that maximizes revenue (assume x and y cannot be negative):

    Max Z = 15x + 20y

    s.t.

    5x + 5y ≤ 40

    4x + y ≤ 4

    What is the maximum revenue at the optimal solution?

    $185

    $120

    $80

    $200

0 0
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Answer #1

Ans:

Using Graphical method:

Point X coordinate (X1) Y coordinate (X2) Value of the objetive function (Z)
O 0 0 0
A 0 8 160
B 8 0 120
C 0 4 80
D 1 0 15

Points O,C,D form the feasible region(green) and point C(0,4) is optimal point.

Maximum revenue=15*0+20*4=80

Correct option is 80 dollars.

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