Let Z be the standard normal variable. Find z if z satisfies the given value. (Round your answer to two decimal places.) P(−z < Z < z) = 0.9802
solution
P(-z < Z < z) =0.9802
P(Z < z) - P(Z < -z) = 0.9802
2 P(Z < z) - 1 =0.9802
2 P(Z < z) = 1 + 0.9802. = 1.9802
P(Z < z) = 1.9802 / 2 = 0.9901
P(Z < 2.33) = 0.9901
z ± 2.33 using z table
z= -2.33 , z= + 2.33
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