The function used in the following program is supposed to take 2 parameters (arguments) and switch the contents of the 2 and send them back to the calling program, but the values are not swapped and both have the same number in them. Select the option that fixes the problem?
void interchange(int &arg1, int &arg2) { arg2 = arg1; arg1 = arg2 ; } int main() { int num1 = 4 , num2 = 5; interchange(num1, num2); cout << "Number 1 : " << num1 << endl; cout << "Number 2 : " << num2 << endl ; return 0; }
1. Need to replace the
code with the following
int temp = arg1;
arg1 = arg2 ;
arg1 = temp ;
2. interchange (&num1, &num2) ; // function call
3. None of the given choices is correct
4. int interchange(int & arg1, int & arg2) // function heading
interchange (&num1, &num2) ; // function call
5. int interchange(int arg1, int arg2) // function heading
1. Need to replace the code with the following
int temp = arg1;
arg1 = arg2 ;
arg1 = temp ;
The function used in the following program is supposed to take 2 parameters (arguments) and switch...
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4. (3 points) Consider the following function reverse, that attempts to reverse an array in place (i.e. without the use of additional storage). It does it by interchanging the first and last elements, then the second and second from last etc. All of the interchanges are done by calling function interchange. Here are the two functions and a main program: #include <iostream> using namespace std; void interchange(int x, int y) int temp: temp = x; x=y: y - tempi }...