The production of a complex chemical needed for anticancer drugs is exponentially distributed with lambda =...
The production of a complex chemical needed for anticancer drugs is exponentially distributed with lambda = 6 kilograms per hour. What is the probability that the production process requires more than 15 minutes to produce the next kilogram of drugs?
Would it be (1/6)e^-(.25/6)?
Homework Answers
Solution:
Given in the question
Lambda = 6
We need to calculate
P(X>(15/60)) we will use exponantial probability
P(X>(15/60)) = e(-lambda*X) = e(-6*0.25) = e^-1.5 = 0.2231
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